Doc #79402 [Fbk->NoF]: Description fix suggestion
| From: | php-bugs at lists dot php dot net | Date: | Sun, 05 Apr 2020 04:22:08 +0000 |
| Subject: | Doc #79402 [Fbk->NoF]: Description fix suggestion | ||
| References: | 1 | Groups: | php.doc.bugs |
| Request: | Send a blank email to doc-bugs+get-17461@lists.php.net to get a copy of this message | ||
Edit report at https://bugs.php.net/bug.php?id=79402&edit=1
ID: 79402
Updated by: php-bugs@lists.php.net
Reported by: simongcc at gmail dot com
Summary: Description fix suggestion
-Status: Feedback
+Status: No Feedback
Type: Documentation Problem
Package: Documentation problem
PHP Version: Irrelevant
Assigned To: cmb
Private report: N
New Comment:
No feedback was provided. The bug is being suspended because
we assume that you are no longer experiencing the problem.
If this is not the case and you are able to provide the
information that was requested earlier, please do so and
change the status of the bug back to "Re-Opened". Thank you.
Previous Comments:
------------------------------------------------------------------------
[2020-03-22 13:37:08] cmb@php.net
Isn't that already sufficiently explained:
| The + operator returns the right-hand array appended to the
| left-hand array; for keys that exist in both arrays, the elements
| from the left-hand array will be used, and the matching elements
| from the right-hand array will be ignored.
------------------------------------------------------------------------
[2020-03-22 00:40:32] simongcc at gmail dot com
Description:
------------
---
From manual page: https://php.net/language.operators.array
---
It is only a problem in description.
In the docs, it states that $a + $b is Union and it is Union of $a and $b.
But it is not completely reflecting the characteristic of the Union in PHP.
Since strictly speaking, an Union should be mutually inclusive of different things.
In PHP, it is only an union of key regardless of value.
So it should be written as
Union of the key in $a and $b and based on $a or vice versa if it is $b + $a. (Because when there
is/are key(s) exist(s) in the first variable, the same key(s) in the second variable will be
ignored)
Test script:
---------------
$a = array('something' => 'interesting', 2);
$b = array('another' => 'interesting thing', 0 => 3);
$c = $a + $b;
$d = $b + $a;
print_r($c);
print_r($d);
------------------------------------------------------------------------
--
Edit this bug report at https://bugs.php.net/bug.php?id=79402&edit=1