Doc #80311 [Com]: jsonb operators not supported

Edit report at https://bugs.php.net/bug.php?id=80311&edit=1 ID: 80311 Comment by: info at towntasks dot com Reported by: boan at jfmedier dot dk Summary: jsonb operators not supported Status: Verified Type: Documentation Problem Package: PDO PgSQL PHP Version: 7.2.34 Block user comment: N Private report: N New Comment: Hello, If you are searching short task or partime jobs, you can follow or visit to apply jobs <a href="https://towntasks.com/">Town Task</a> <a href="https://towntasks.com/">Part Time Jobs </a> <a href="https://towntasks.com/">Short Tasks</a> Previous Comments: ------------------------------------------------------------------------ [2020-11-03 14:20:45] cmb@php.net This is expected behavior, because the question mark is considered to be a placeholder. As of PHP 7.4.0, it is possible to escape the question mark by doubling it[1]. Changing this to doc problem, since apparently that escaping mechanism is not yet documented in the manual proper[2]. [1] <https://www.php.net/manual/en/migration74.new-features.php#migration74.new-features.pdo> [2] <https://www.php.net/manual/en/pdo.prepared-statements.php> ------------------------------------------------------------------------ [2020-11-03 14:06:23] boan at jfmedier dot dk Description: ------------ When trying to query a jsonb field in postgresql with the questionmark operator, we get error code 42601. $pdo->query("SELECT * FROM term_template tt WHERE (sites->0) ? 'site_id'"); `"ERROR: syntax error at or near "$1" LINE 1: SELECT * FROM term_template tt WHERE (sites->0) $1 'site_id'..."` See jsonb operators here: https://www.postgresql.org/docs/10/functions-json.html The query works when executed within a database tool. Test script: --------------- Fixture data in DB "sites" column: [{"site_id": "example.org"}] ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=80311&edit=1