Doc #79915 [Com]: Explanation about umask parameter

Edit report at https://bugs.php.net/bug.php?id=79915&edit=1 ID: 79915 Comment by: k dot imiasaldamo dot 9881 at gmail dot com Reported by: petra dot bertova at gmail dot com Summary: Explanation about umask parameter Status: Open Type: Documentation Problem Package: Filesystem function related Operating System: ubuntu PHP Version: Irrelevant Block user comment: N Private report: N New Comment: That was so amazing. (https://www.landstaronline.me/)github.com Previous Comments: ------------------------------------------------------------------------ [2020-07-30 18:39:47] requinix@php.net As stated in the top comment, umask is about revoking permissions, not granting them. This is how the standard umask(2) works. https://man7.org/linux/man-pages/man2/umask.2.html ------------------------------------------------------------------------ [2020-07-30 11:11:02] petra dot bertova at gmail dot com Description: ------------ --- From manual page: https://php.net/function.umask --- Umask function seems to accept parameter in reverse binary code. Full access is not umask(0777), but umask(0000) -rwxrwx--- is not umask(0770), but umask(0007) -rwxrwxr-x is not umask(0775), but umask(0003) Please, update documentation and add more examples. Actual result: -------------- When I write umask(0777) I have no permissions to a directory/file When I write umask(03) I have -rwxrwxr-x permissions to a directory/file ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=79915&edit=1