Bug #51737 [Csd]: Having a bug when using date_diff($t1,$t2)

Edit report at http://bugs.php.net/bug.php?id=51737&edit=1 ID: 51737 Updated by: aharvey@php.net Reported by: iggukk at gmail dot com Summary: Having a bug when using date_diff($t1,$t2) Status: Closed Type: Bug Package: Documentation problem Operating System: Win XP PHP Version: 5.3.2 Assigned To: aharvey New Comment: This bug has been fixed in the documentation's XML sources. Since the online and downloadable versions of the documentation need some time to get updated, we would like to ask you to be a bit patient. Thank you for the report, and for helping us make our documentation better. Added an example anyway, just to be on the safe side. :) Previous Comments: ------------------------------------------------------------------------ [2010-05-04 12:07:01] aharvey@php.net Automatic comment from SVN on behalf of aharvey Revision: http://svn.php.net/viewvc/?view=revision&revision=298955 Log: Added an example to make clearer the misunderstanding that led to bug #51737 (Having a bug when using date_diff($t1,$t2)). ------------------------------------------------------------------------ [2010-05-04 11:23:07] iggukk at gmail dot com Thanks a lot, aharvey you're great. I should have figured there was something to find in the format but my mind is kinda stuck this morning. Nevermind about the documentation. I should have guessed that there were more tags than %d. Like in all the date/time functions (doh!). I guess I deserve a /slap for that. Going back to work. Thanks again. ------------------------------------------------------------------------ [2010-05-04 11:11:07] aharvey@php.net Not a bug, since you probably want %a (which is the total number of days in the interval) rather than %d. %d only shows the number of days left over after date_diff() has calculated the number of months and years: in your first example, the interval is basically "1 month 0 days", so %d returns 0. (If you try "%m month(s) %d day(s)" as the format string, that will probably be a bit clearer.) Nevertheless, the documentation could probably be a touch clearer on this point. Morphing into a documentation bug; I'll see if I can make it a bit more obvious in one of the examples what %d does. ------------------------------------------------------------------------ [2010-05-04 11:04:01] iggukk at gmail dot com Huh, sorry about that, and thanks for answering so quickly. echo $interval->format('%R%d days'); simply from the example on php manual. Just tried to feed the dates in different formats like 12.04.2010 and 12.03.2010, (instead of 2010-04-12) it seems to give the same result in final. ------------------------------------------------------------------------ [2010-05-04 10:57:43] aharvey@php.net The test script you've provided doesn't work, since echoing a DateInterval object isn't supported. How are you actually outputting $interval? ------------------------------------------------------------------------ The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online at http://bugs.php.net/bug.php?id=51737 -- Edit this bug report at http://bugs.php.net/bug.php?id=51737&edit=1