cvs: phpdoc /en/reference/pcre/functions preg-replace.xml

From: Date: Thu, 23 Jan 2003 04:06:26 +0000
Subject: cvs: phpdoc /en/reference/pcre/functions preg-replace.xml
Groups: php.doc 
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pollita Wed Jan 22 23:06:26 2003 EDT Modified files: /phpdoc/en/reference/pcre/functions preg-replace.xml Log: Typo fixes Index: phpdoc/en/reference/pcre/functions/preg-replace.xml diff -u phpdoc/en/reference/pcre/functions/preg-replace.xml:1.5 phpdoc/en/reference/pcre/functions/preg-replace.xml:1.6 --- phpdoc/en/reference/pcre/functions/preg-replace.xml:1.5 Wed Jan 22 20:04:49 2003 +++ phpdoc/en/reference/pcre/functions/preg-replace.xml Wed Jan 22 23:06:26 2003 @@ -1,5 +1,5 @@ <?xml version="1.0" encoding="iso-8859-1"?> -<!-- $Revision: 1.5 $ --> +<!-- $Revision: 1.6 $ --> <!-- splitted from ./en/functions/pcre.xml, last change in rev 1.2 --> <refentry id="function.preg-replace"> <refnamediv> @@ -42,7 +42,7 @@ notation for your backreference. <literal>\\11</literal>, for example, would confuse <function>preg_replace</function> since it does not know whether you want the <literal>\\1</literal> backreference followed by a literal <literal>1</literal>, - or the <literal>\\11</literal> backreference followed nothing. In this case + or the <literal>\\11</literal> backreference followed by nothing. In this case the solution is to use <literal>\${1}1</literal>. This creates an isolated <literal>$1</literal> backreference, leaving the <literal>1</literal> as a literal. @@ -55,7 +55,7 @@ <?php $str = "April 15, 2003"; $pattern = "/(\w+) (\d+), (\d+)/i"; -$replacement = "\${1}1,\$3","April 15, 2003"; +$replacement = "\${1}1,\$3"; print preg_replace($pattern, $replacement, $string); /* Output

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