#25910 [Opn->Csd]: Error in example 1 in the mysql_fetch_field doco

ID: 25910 Updated by: ali@php.net Reported By: dissent at 0--0 dot org -Status: Open +Status: Closed Bug Type: Documentation problem PHP Version: Irrelevant New Comment: This bug has been fixed in CVS. In case this was a PHP problem, snapshots of the sources are packaged every three hours; this change will be in the next snapshot. You can grab the snapshot at http://snaps.php.net/. In case this was a documentation problem, the fix will show up soon at http://www.php.net/manual/. In case this was a PHP.net website problem, the change will show up on the PHP.net site and on the mirror sites in short time. Thank you for the report, and for helping us make PHP better. Previous Comments: ------------------------------------------------------------------------ [2003-10-19 11:11:02] dissent at 0--0 dot org Description: ------------ In the english version of the manual, the documentation for mysql_fetch_field, there's an error in example 1. The second line in the while loop should use $i, not $result. The line $meta = mysql_fetch_field($result); Should be: $meta = mysql_fetch_field($i); Expected result: ---------------- while ($i < mysql_num_fields($result)) { echo "Information for column $i:<br />\n"; $meta = mysql_fetch_field($i); if (!$meta) { echo "No information available<br />\n"; } Actual result: -------------- while ($i < mysql_num_fields($result)) { echo "Information for column $i:<br />\n"; $meta = mysql_fetch_field($result); if (!$meta) { echo "No information available<br />\n"; } ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=25910&edit=1