#36758 [Bgs]: eval not behaving like in documantation

ID: 36758 Updated by: colder@php.net Reported By: khan dot shadow at gmail dot com Status: Bogus Bug Type: Documentation problem PHP Version: Irrelevant New Comment: There are a lot of non-sense in your post: 1) variables don't have to be escaped inside single quotes, the evaluated code will result to a parse error. 2) you can't use echo in a return context, because echo is a language construct that doesn't behave like a function. 3) your eval() will always be evaluated as false : "As of PHP 4, eval() returns NULL unless return is called in the evaluated code". Previous Comments: ------------------------------------------------------------------------ [2006-03-16 12:12:39] mike@php.net Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Due to the volume of reports we can not explain in detail here why your report is not a bug. The support channels will be able to provide an explanation for you. Thank you for your interest in PHP. Then don't use the echo statement. ------------------------------------------------------------------------ [2006-03-16 12:00:53] khan dot shadow at gmail dot com Description: ------------ " In case of a parse error in the evaluated code, eval() returns FALSE. In case of a fatal error in the evaluated code, the whole script exits." Reproduce code: --------------- $page = 'for(\$i=0;\$i<=2;\$i++){?>'; $page .= '<b>test code</b>'; $page .= '<? } ?>'; ' $cad = $page; $cad = @eval($cad)==false ? echo $cad : ob_get_contents(); Expected result: ---------------- $cad should be $cad='<b>test code</b><b>test code</b><b>test code</b>' Actual result: -------------- $cad is echod to the screen ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=36758&edit=1