Re: diplaying the path

actually: If the php directive register_globals is on, then $HTTP_REFERER will exist. Otherwise it will not. (or course that assumes a value exists at all). Regardless of the register_globals setting, you can do: // Works since PHP 3 (forever)* print $HTTP_SERVER_VARS['HTTP_REFERER']; // Works since PHP 4.1.0 print $_SERVER['HTTP_REFERER']; Btw, $GLOBALS['HTTP_REFERER'] === $HTTP_REFERER. And lastly, since PHP 4.2.0 the register_globals directive defaults to off, which is what Jim was indirectly referring to. See also extract(). Regards, Philip Olson * For versions older then 4.0.3 see also the track_vars directive, it should be on. On Fri, 31 May 2002, Jim lucas wrote: > depending on what version of php you are running, you can use > $GLOBALS['HTTP_REFERER'] or on newer versions you can use > $_SERVER['HTTP_REFERER'] > > Jim Lucas > ----- Original Message ----- > From: "Kris Vose" <KVose@alidaconnection.com> > To: <php-general@lists.php.net> > Sent: Friday, May 31, 2002 9:19 AM > Subject: [PHP] diplaying the path > > > > Is there a variable/function in php that will display the url location of > the hyper-link that brought them to the current page. Thanks in advance. > > > > Kris Vose > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >