RE: [PHP] [PLEASE HELP] Passing variable to new page.

Javascript, being silly, has silly string rules: function pop1($id) { window.open("info.php?prod_id="+ $id); } --- Scott Hurring Systems Programmer EAC Corporation ScottH@eac.com Voice: 201-462-2149 Fax: 201-288-1515 > -----Original Message----- > From: Chris Knipe [mailto:savage@savage.za.org] > Sent: Thursday, June 06, 2002 2:50 PM > To: php-general@lists.php.net > Subject: Re: [PHP] [PLEASE HELP] Passing variable to new page. > > > > echo "<script language=\"JavaScript\">"; > > echo" function pop1() {"; > > echo" window.open(\"info.php?prod_id=$result[0]\"); }"; \\ > $result[0] is > > variable that stores id of the image in database > > echo "</script>"; > > > > I am calling this function in the following manner: echo"<img > > onclick=\"pop1();\""; > ^^^^^^^^^^^^^^^^^^^^^ > > You're not passing a value to the variable. Try using > something like: (i'm > NO java guru, and this definately isn't the list for java)... > > function pop1($id) { > window.open("info.php?prod_id=$id"); > } > > and > > <img src="blah" onclick="pop1(12345)"> > > Where 12345 is the product ID that you assigned to variable > prod_id, which > will in return be displayed in the second PHP file. You're problem's > related to the java script, not assigning the value to the > variable. This > isn't a PHP issue. > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >