Re: is preg_replace the fastest way?

I think this is similar to what you're asking for, but it's probably slower (you have to split(), traverse, then join()) foreach ($noiselist as $noise) foreach ($inputlist as $input) if ($noise == $input) // do something -- Scott Hurring Systems Programmer EAC Corporation scott (*) eac.com -- "Zac Hillier" <zac@affectors.net> wrote in message news:007f01c2118a$f7a0ba20$667ba8c0@ws... > Hi All, > > I'm writing a search facility and am stripping noise words from a string > (The string contains between 50 - 200 words). Presently I'm importing a text > file of noise words (The noise words file contains almost 1000 words) then > using : > > #-- remove noisewords > $cntLmt = count($noise_words); > for ($i=0; $i<$cntLmt; $i++) { > $filterword = trim(strtolower($noise_words[$i])); > $filtered = preg_replace("/(\b$filterword \b)/x"," ",$filtered); > } > > to remove these noise words. > > However I'm wondering if it would be quicker to separate the $filtered > string and then look for the words in a noise words string. If so how would > I do this and remove the words? > > Thanks > > Zac >