Re: Code Structure/Errors

Quick soln. is to put a "@" symbol in front of the error generating line. E.g.@$i++; actual soln. would be to do some initialization like $i = 0; outside your while loop and $last_name=""; > I'm just curious if there's a way to restructure my code so as to avoid > getting "Undefined Variable" errors. I keep getting them and I know they're > nothing to worry about for the most part, I'd like to get rid of them > without turning off error reporting if possible. In the following code, I > get an undefined variable error for $i and for $last_name, is there anything > I can do to actually define them? $last_name is a variable produced by my > MySQL query, $i is just a counter: > > while ($row = mysql_fetch_array($result)) { > extract($row); > $i++; > if($i=="1") { > print "<tr>\n"; > } > > if($last_name) { > <print stuff here> > } else { > <print other stuff> > } > ... > if ($i=="5") { > print "</tr>\n"; > $i=0; > } > } > > Thanks! > > Jason Soza > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -Pushkar S. Pradhan