RE: Re[2]: [PHP] beginner in PHP

> -----Original Message----- > From: Stuart Dallas [mailto:stuart@sharedserver.net] > Sent: Thursday, June 13, 2002 2:53 PM > To: Phillip Perry > Cc: Tim Ward; Martin Towell; Tom Rogers; Php > Subject: Re[2]: [PHP] beginner in PHP > > > On Thursday, June 13, 2002 at 7:44:39 PM, you wrote: > > > Yes, here is the checkout code I used... > > > function chout(){ > > session_destroy(); > > unset ($mycart); > > unset ($cart_items); > > echo "<p>Thank you for shopping!</p>"; > > } > > > Any suggestions? > > Try this... > > function chout(){ > global $mycart, $cart_items; > session_destroy(); > unset ($mycart); > unset ($cart_items); > echo "<p>Thank you for shopping!</p>"; > } Still won't work. All that the "global" statement does is make the copy of the variable inside the function be a *reference* to the global copy -- it's basically equivalent to $mycart = & $GLOBALS['mycart']; So, when you unset($mycart) within the function, all you're unsetting is the reference -- the actual global variable is completely unaffected. Thus, the only way to unset a global variable is to reference it in the global context. One way to do this might be: function chout(){ session_destroy(); unset ($GLOBALS['mycart']); unset ($GLOBALS['cart_items']); } Alternatively, just do it in the global context, outside any function. Cheers! Mike --------------------------------------------------------------------- Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: m.ford@lmu.ac.uk Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211