php execution a server side program updated problem please help

Hello php-general, Hello php-general, Dear php list, I've got completely lost in program execution under php. I need to run a command grab it's output for the next processing, So I wrote a script: <? $output = shell_exec("uudeview -i /bla/bla.txt -p /bla/bla/"); echo "<pre>"; echo $output; echo "</pre>"; ?> And I get nothing :(. Script like below: <? $output = shell_exec("uudeview"); echo "<pre>"; echo $output; echo "</pre>"; ?> Work fine outputting me command line parameters. Also when i run this file via linux console i get the following mess: ******************************************************************************* php 6.php X-Powered-By: PHP/4.0.6 Content-type: text/html Loaded from /bla/bla.txt: '' (cs99g021.idx): cs99g021.idx part 1 be gin end yEnc <html><body><pre> Found 'cs99g021.idx' State 16 yEnc Parts begin 1 end OK File successfully written to /bla/bla/cs99g021.idx 1 file decoded from 1 input file, 0 failed </pre></html></body> I think it must be in the other way, like this: <html><body><pre> Loaded from /bla/bla.txt: '' (cs99g021.idx): cs99g021.idx part 1 be gin end yEnc Found 'cs99g021.idx' State 16 yEnc Parts begin 1 end OK File successfully written to /bla/bla/cs99g021.idx 1 file decoded from 1 input file, 0 failed </pre></html></body> Please give me some clues where is my mistake, i'm getting little nuts. -- Best regards, Latex mailto:freeman@submission.org.ru