Re: help with eval problems...

From: Date: Sat, 06 Jul 2002 07:56:37 +0000
Subject: Re: help with eval problems...
References: 1  Groups: php.general 
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On Fri, 5 Jul 2002, Kelly Meeks wrote: > If I had this information stored in a database field, > <img src="<? echo $content_output["site_logo"]; ?>"> > > how could I assign it to a variable and output it? you have to ?> first to leave php mode so you can do $content_output = "logo.gig"; $code = "<img src='<?php echo $content_output; ?>'>"; eval("?>$code"); which will echo the outut or catch it with output buffering $content_output = "logo.gig"; $code = "<img src='<?php echo $content_output; ?>'>"; ob_start(); eval("?>$code"); $evaled_code = ob_get_contents(); ob_end_clean(); I have used arrays in evals before you have to watch the quotes. Paul Roberts roberts_paul@bigfoot.com ++++++++++++++++++++++++

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