Re: Execute script then output image.

I found it. I used header("Location: http://www.yoursite.com/images/stat.gif"); -- JJ Harrison webmaster@tececo.com www.tececo.com "David Otton" <david.otton@overnetdata.com> wrote in message news:7ltqiu0e2i0guh3c87sesif0n3k7lpjfh1@4ax.com... > On Thu, 11 Jul 2002 22:01:03 +1000, you wrote: > > >> You need to output the correct content-type header for the image (eg > >> image/gif), take it's size and output it as content-length, and > >> suppress error reporting. Then output the image data. > > >There was a much simpler way. It just said the location of the file. > > > >I could use your method but the other one was much simpler. > > Is this what you meant? > > > http://news.php.net/article.php?group=php.general&article=106348 > > http://news.php.net/article.php?group=php.general&article=106370 > > Looks like the same thing I suggested to me... > > $filename = "your/file.gif"; > > // output the correct content-type header > header("Content-Type: image/gif"); > > // take it's size and output it as content-length > header("Content-length:".filesize($filename)); > > // Then output the image data > readfile($filename); > > djo >