is_null question

Hi Everyone, Here's my problem: I'd like to make the printing of some text dependent on whether or not a variable is null. In the following example, when $row[1] is null, what gets printed on the page is "Email: ". I'd like the script to not print "Email:" if row[1] is null. It looks like I should be using is_null(), but I'm not sure how to use it, especially since all of this is embedded in a print statement. while ($row = mysql_fetch_row ($result)) { print ("\t<tr bgcolor=\"#ff9900\">\n\t\t<th>$row[0]</th>\n</tr>\n\t<tr class=\"default\" bgcolor=\"#ffffff\">\n\t\t<td><p>$row[10]</p><p>Email: <a href=\"mailto:$row[1]\">$row[1]</a><br />Phone: $row[2]</p>\n\n<p>Address: $row[3]<br />$row[4]<br />$row[5] $row[6] $row[7]</p> <p>URL: <a href=\"$row[8]\" target=\"_blank\">$row[8]</a></p></td></tr>"); } Instead of just printing Email: $row[1], I'd like to test whether it's null first--maybe something like this? if (is_null($row[1])) print " " else print ("Email: $row[0]") but can I put that line inside of another print statement? if so, do I have to escape the quotation marks? Please forgive my confusion--I'm new to programming in general and PHP in particular. Thanks in advance for your help. best, Matt