POST question

From: Date: Sat, 20 Jul 2002 05:39:57 +0000
Subject: POST question
Groups: php.general 
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I have a page with a form that has a drop down menu that I can select different items that I want to display on another page where I can add more information to be entered into a database. I can do that by using this on the page that displays. while ($row = mysql_fetch_array( $sql_result )) { $_POST["asset_type"] = $row["asset_type"]; } What I want to do is have a different page display for different choices. So if I choose one type of asset to add, then submit it to be added to the database, I want to have a script that reads what the selection was and displays the page that matches the type of asset that matches it. I think the best way to do this is to have the "$_POST["asset_type"]" go to a second page that decides if $_POST["asset_type"] = "Computer" go to the page for adding computer information, or if it equals "Printer" is goes to the page for entering printer information. The question I have is how can I make sure the $_POST["asset_type"] carries onto a third page and how do I make it so that when a selection is made, it opens the correct third page? I hope I explained this well enough to understand. Thanks, Mike

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