Re: finding if $key has value

Try something like this instead (untested): while (list($k, $v) = each($data)) { if (substr($k,0,1) == 'a') { if (!isset($v)) { $sectionA_error = 1; } else { $sectionA_error = 0; } } } You could also try array_key_exists() instead of isset() ... both should do the job. Michael > here is what i try to accpmplish: > $key "name's" in an array are: a1, a2, a3, .... . > $value dependes weather it has been checked, selected or entered. > > while (list($k, $v) = each($data)) > { > for ($i=0; $i<count($k); $i++) { > if (substr ($k[$i], 0, 1) == 'a') { > if ($k == !$v) { // <-- ???? > $sectionA_error = 1; > } else { > $sectionA_error = 0; > } > } > } > } > if ($sectionA_error) { > echo "Nothing entered.\n<br>"; > } else { > echo "at least one entry.\n<br>"; > } > > what i'm trying to get is: > if there is a least one or doesn't matter how many values error = 0, > if there is no value than error =1. > > cheers, > > Peter > > > -- -------------------------------- n i n t i . c o m php-python-perl-mysql-postgresql -------------------------------- Michael Hall ninti@ninti.com --------------------------------