RE: [PHP] Re: Using fopen()/fread()/fscanf()

I'm thinking that you need to remove the: $contents = fread($filename, 1000000); line. This is probably making the file pointer point to the end of the file. -----Original Message----- From: Jason Soza [mailto:solja@gci.net] Sent: Tuesday, July 23, 2002 4:17 PM To: David Robley; php-general@lists.php.net Subject: RE: [PHP] Re: Using fopen()/fread()/fscanf() I'm fairly certain that fopen() is working fine - I can echo "$contents"; and it works great, but it displays the entire page that I fetched. I just want certain parts of the page and unfortunately, fscanf() doesn't seem to think $contents or $filename are valid. Just more info on this, I tried replacing fscanf($filename,...) with fscanf($contents,...) and got the same result. Thanks, Jason Soza -----Original Message----- From: David Robley [mailto:robleyd@paradise.net.nz] Sent: Monday, July 22, 2002 8:37 PM To: php-general@lists.php.net Subject: [PHP] Re: Using fopen()/fread()/fscanf() In article <JNEPLIKJKFFIIBCBFMJFEEGGCCAA.solja@gci.net>, solja@gci.net says... > I think I'm pretty close to getting this right (maybe!), I've been reading > through the manual, but can't seem to work it out. I keep getting this > error: > > [Mon Jul 22 19:03:24 2002] [error] PHP Warning: Supplied argument is not a > valid File-Handle resource in index.php on line 66 > > I'm trying to open a URL, read the contents, then pull out specific info > found between specific HTML tags. This is what I have so far: > > 63| <?php > 64| $filename = > > fopen("http://www.kinyradio.com/juneaunews/latest_juneau_news.html", > "r"); > 65| $contents = fread($filename, 1000000); > 66| while($headlines = fscanf($filename, "<p style=\"padding-left: > 45\"><font face=\"Verdana\" size=\"3\"><b>%[a-zA-Z0-9,. > ]</b></font>", > $headline)) { > 67| extract($headlines); > 68| print "<a > href=\"http://www.kinyradio.com/juneaunews/latest_juneau_news.html\">$headli > ne</a><br>"; > 69| } > 70| fclose($filename); > 71| ?> > > Any ideas? Any other functions I could try instead of fscanf()? That error indicates that fopen failed to open the requested file. Given that the URL works fine in a browser, is it possible that your php is not configured to do remote fopen? Check the setting of allow_url_fopen in phpinfo() It is a good idea to test the result of such calls before trying to use the result: fopen('Whatever') or exit('Couldn't get it, Boss!'); or if(fopen('whatever') { do good things; }else{ bleat vigorously; } Cheers -- David Robley Temporary Kiwi! Quod subigo farinam -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php