Re: Re[2]: [PHP] imagecolortransparent()

thanks it worked ^^ -Nick "Tom Rogers" <trogers@kwikin.com> wrote in message news:2735331183.20020723134503@kwikin.com... > Hi, > > Tuesday, July 23, 2002, 5:16:43 AM, you wrote: > > N> "Tom Rogers" <trogers@kwikin.com> wrote in message > N> news:16878540805.20020722210409@kwikin.com... > >> Hello Nick, > >> > >> Monday, July 22, 2002, 8:47:39 PM, you wrote: > >> > >> N> i get php to allocate a colour then make it transparent using > >> N> imagecolortransparent() > >> > >> N> instead of turning it transparent it becomes black. > >> > >> N> Is it something i'm doing wrong? can anyone help me? > >> > >> N> thanx in advance > >> > >> Post a bit of the code so we can see what you are doing > >> > >> -- > >> Tom > >> > > N> $im = imagecreate($size, 21); > > N> $bgcolour = > N> imagecolorallocate($im,hexdec(substr($table[bg],0,2)),hexdec(substr($table[b > N> g],2,2)),hexdec(substr($table[bg],4,2))); > N> $fontcolour = > N> imagecolorallocate($im,hexdec(substr($table[fg],0,2)),hexdec(substr($table[f > N> g],2,2)),hexdec(substr($table[fg],4,2))); > > N> if ($table[bg] == "no") { > N> $trans = imagecolortransparent ($im,$bgcolour); > N> } > > probably what you need is: > > $im = imagecreate($size, 21); > if ($table[bg] == "no") { > $bgcolour = imagecolorallocate($im,1,1,1); > $trans = imagecolortransparent ($im,$bgcolour); > } > else{ > $bgcolour = imagecolorallocate($im,hexdec(substr($table[bg],0,2)),hexdec(substr($table[b g],2,2)),hexdec(substr($table[bg],4,2))); > } > $fontcolour = imagecolorallocate($im,hexdec(substr($table[fg],0,2)),hexdec(substr($table[f g],2,2)),hexdec(substr($table[fg],4,2))); > > > > > > -- > Best regards, > Tom >