filling an array
| From: | Steve Buehler | Date: | Fri, 26 Jul 2002 20:42:30 +0000 |
| Subject: | filling an array | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-109881@lists.php.net to get a copy of this message | ||
Thank You Andrey, Matt and Martin for your answers. To summarize for everyone, here are the answers:
From Andrey (tested, works):
for($m=1;$m<=5;$m++){
$div_id[$m]=${'divid'.$m};
}
From Matt:
for($m=1;$m<=5;$m++){
$varName = 'divId' . $m;
$div_id[$m]=${$varName}
}
From Martin:
for($i =0; $i < 5; $i++) {
$offset = $m + 1;
$divid[$m] = $div_id{$offset};
}
At 10:55 PM 7/26/2002 +0300, you wrote:
----- Original Message ----- From: "Steve Buehler" <steve@vespro.com> To: "PHP" <php-general@lists.php.net> Sent: Friday, July 26, 2002 10:48 PM Subject: [PHP] filling an array Can anyone tell me what I am doing wrong? I am essentially trying to do this: $divid[1] = $div_id1; $divid[2] = $div_id2; $divid[3] = $div_id3; $divid[4] = $div_id4; $divid[5] = $div_id5; But I was looking for a tighter way, like the following (which does not work): for($m=1;$m<=5;$m++){ $div_id[$m]=$divid$m; } Can anybody tell me how to do this in a "for" statement? Thanks In Advance Steve -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean. ow3 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean. ow3-- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean. ow3