Re: Calling a function without variable params
| From: | lallous | Date: | Sat, 27 Jul 2002 09:22:51 +0000 |
| Subject: | Re: Calling a function without variable params | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-109941@lists.php.net to get a copy of this message | ||
you can pass an unlimited number of variable through the array()
constructor.
as:
data_interface(array($table1, $table2, $table3))
you can use an Array manipulation functions for that order too.
good luck,
"Mathieu Dumoulin" <mdumoulin@groupimage.com> wrote in message
news:20020727012052.51058.qmail@pb1.pair.com...
> Ok, here i made a function that can accept an unknown number of params.
>
> In fact, it's a data interface for a mysql database, when i call the
> object's constructor it is in possibility to pass any number of table
names
> from 1 to x. Now i got this other class called a data interfacer which
sends
> a certain number of tables to the data interface constructor. I tried
doing:
>
> $interface = new data_interface($table1, eval("$table2, $table3,
$table4"));
> $interface = eval("new data_interface($table1, $table2, $table3,
$table4)");
>
> and various other tries. The thing is i can't know how many tables can be
> transfered from the data interfacer to the data_interface. So i could make
a
> if..elseif...elseif until i reach something like 10 tables but still, it's
> not a good practice, i'm sure there is a way to emulate real parameters
when
> they are needed and skip them in the call if you don't have them.
>
> Can anybody help me out?
>
> InsaneCoder
>
>