RE: [PHP] mktime() question - SOLVED

[snip] I need to subtract months by their abbreviated month name, so shouldn't this work? print(date("M", mktime(date("M")-$i)); and if I loop; Aug Jul Jun May ........ [/snip] Apparently not. But you can subtract by total hours in a given period, so for an average I chose 30 days * 24 hours (720); $i = 36; $h = 720; while($i > 0){ print(date("M", mktime(date("M")-$h)));print(date("Y"));print("<br>"); $i--; $h = $h + 720; } which results in Jul2002 Jun2002 May2002 Apr2002 Mar2002 Feb2002 Jan2002 Dec2002 Nov2002 Oct2002 Sep2002 Aug2002 Jul2002 Jun2002 May2002 So now all I have to do is sove the year rollover, which I think I can do the same way. It'd be so much easier if mktime worked as the documentation said, but after many iterations of different things this is what I was able to come up with. Jay Carpe Ductum - Sieze the tape ********************************************* * Texas PHP Developers Meeting Spring 2003 * * T Bar M Resort & Conference Center * * New Braunfels, Texas * * Interested? Contact; * * jay.blanchard@niicommunications.com * *********************************************