Re: isset($var) && !empty($var) same time!
| From: | Verdana Musone | Date: | Sat, 03 Aug 2002 07:45:08 +0000 |
| Subject: | Re: isset($var) && !empty($var) same time! | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-110943@lists.php.net to get a copy of this message | ||
I always set error_reporting(E_ALL) oR error_reporting(2047), but i have never got any errors when
just use empty()
to determine whether a variable is set.
If the variable is: 0, null, not set or an empty string.
Then the empty() will return true.
It's unnecessary to call isset() first.
----- Original Message -----
From: lallous
Sent: 2002年8月3日 15:01
To: php-general@lists.php.net
Subject: Re: [PHP] isset($var) && !empty($var) same time!
Just use empty() ?!
With error_reporting(E_ALL) you'll get a bunch of warnings if you only use
empty() w/o the isset() !
use isset() first and then check wheter empty or not empty!
so there is not one function that tests for empty and isset same time!?
Elias
"Analysis & Solutions" <danielc@analysisandsolutions.com> wrote in message
news:20020802141158.GA27625@panix.com...
> On Fri, Aug 02, 2002 at 04:48:17PM +0200, lallous wrote:
> >
> > function issne($var)
> > {
> > return isset($var) && !empty($var) ? true : false;
> > }
> >
> > is there is any builtin function that does that? (one function call).
>
> Yes. Just use empty(). It automatically checks if the variable is:
> not set
> null
> an empty string
> zero
>
> If any of them are true, the empty() function returns true. You don't
> need your function at all.
>
> --Dan
>
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