Re: quick form question

"Alexander Ross" <alexross@bleen.net> wrote in message news:20020808162929.17218.qmail@pb1.pair.com... > I have a .php with a simple form in it to populate a table in a mysql db. > When the user clicks submit, I check to make sure he/she entered the > required info and if all is well, I add the data to teh DB. If he/she left > out some info, I echo "You left out some info" and I redisplay the form. > When I do this all the info that the user typed originally is gone. Whats > the easiest way to put back what he/she already typed? Thanks > I am not sure of what you require but will respond according to my understanding... I am assuming your send page is to the same page... i.e. If you have myForm.php coding the form you have something as follows: <? //myForm.php echo '<form name = myForm action=myForm.php method=post>'; if((empty($var1))||(empty($var2))||....{ if(empty($var1)){ echo '<input name = var1 .... >'; } // Notice the locking of Strings So as not to lose // info when the page is sent... This is done // by the backslashes... else{ echo "<input type = hidden name = \"var1\" value = \"var1\">"; if(empty($var2)){ echo '<input name = var2 ... >'; } else{ echo "<input type = hidden name = \"var2\" value = \"var2\">"; } echo ' ...The Submit button...'; } else{ .... // Algorithmically... ... Now you can connect to your DB and Place the variables in their appropriate fields via php and SQL Query commands... echo "DONE!"; } This way only the unfilled fields that you deem neccessary will reappear and Whatever she has already entered is stored as a hidden variable but will be visible when need for use... Hope this helps... Spike...