Re: Help needed about queries with MySQL, thanks.

Thanks for your suggestion ... Yes, I tried to print $sessionID (using echo()) and I get the right value (the one I am looking for) ... Though the query does not work. Any other idea ??? Thanks again ! Jean-Marc ----- Original Message ----- From: "Jason Wong" <php-general@gremlins.com.hk> To: <php-general@lists.php.net> Sent: Sunday, August 18, 2002 11:53 AM Subject: Re: [PHP] Help needed about queries with MySQL, thanks. > On Sunday 18 August 2002 17:45, Jean-Marc Godart wrote: > > > I have a MySQL database (called "sessions") with a auto-increment INT field > > called "sessionID". I try to check if there is already a record in this > > database with a given sessionID, which is called $sessionID in PHP. I use > > this query, which must be wrong (but I cannot find out why !!!) : > > > > SELECT * FROM sessions WHERE sessionID = $sessionID > > > > Even though there is already a record with the right sessionID, my program > > does not find it (I always get 0 when using mysql_num_rows() after the > > query). Though, if I replace "$sessionID" by, for example 4, then that > > works and it says there is already a record with that ID. > > > > I guess the problem comes from comparing two different kinds of variables, > > but I can't fix it ... Could anyone please help ? By advance, thank you !!! > > Have you tried printing out $sessionID to see whether it contains what you > think it contains? > > -- > Jason Wong -> Gremlins Associates -> www.gremlins.com.hk > Open Source Software Systems Integrators > * Web Design & Hosting * Internet & Intranet Applications Development * > > /* > Under capitalism, man exploits man. Under communism, it's just the opposite. > -- J.K. Galbraith > */ > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > >