Re: getting directory info

This is giving me a parse error: <?php $path = '/usr/local/...full.path.snipped.../httpdocs/thumbnails/'; $dir = opendir($path) or die("Could not open $dir"); while ($file = readdir($dir)){ if (stristr($file, 'jpg') || stristr($file, 'jpeg')){ echo "<A HREF=/enlargements/$file>$file</A><BR>\n"; } } ?><BR> This is the only PHP on the page, so it arguably has to be in the above... :-( Wm "Richard Lynch" <rich@phpbootcamp.com> wrote in message news:php.general-114289@news.php.net... > > <?php > $path = '/full/path/to/your/jpeg/dir/'; # Be sure it's world-readable! > $dir = opendir($path) or die("Could not open $dir"); > while ($file = readdir($dir)){ > if (stristr($file, 'jpg') || stristr($file, 'jpeg')){ > echo "<A HREF=$file>$file</A><BR>\n"; > } > } > ?>