RE: [PHP] New as of today

if you have each filename on a new line, then use file() to grab the contents. It returns an array, each line is an element in the array. You can then do what you want with the array HTH Martin -----Original Message----- From: stu9820 [mailto:stu9820@westga.edu] Sent: Friday, August 30, 2002 1:08 PM To: php-general@lists.php.net Subject: [PHP] New as of today Im new to PHP (came from ASP). I'm trying to make pictures (.jpgs) come out of a folder and display on a page. Here is my code so far: <?php $fileLoc = "Bid2002/pictures.txt"; $zFile = fopen($fileLoc, "r"); $zContents = fread($zFile, filesize($fileLoc)); fclose($zFile); echo "<a href=test.php>$zContents<br></a>"; ?> I dont have database support on the server i use (school server). I have all the picture names in a text file and i want to pull out the name of pictures from the text file and make it pull out of the picture folder. Is there an easier way to do this? Or is this the best way. ASP is very because you can loop through the file and I thought I could do it with php but it ends up in one big link. Thanks in advance. Jeff UWG Student stu9820@westga.edu -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php