Re: Reg exp help

> Take for example: > > 194.236.30.24 - - [30/Aug/2002:11:46:29 +0200] "GET > /bildgalleri/createjpg.php?url=/v044&file=v044_27.jpg HTTP/1.1" 200 > 8874 > 217.215.84.222 - - [30/Aug/2002:11:46:39 +0200] "POST /weblogg.php > HTTP/1.1" 200 3149488 [more loglines] > > Here I'ld like to remove all lines that looks like 217.215.84.222 some > text ending with line break… > > How should the reg exp look? Try this: preg_replace( "/^217.215.84.222.*\n/m", "", $log ) The second argument, currently empty, can be used as a replacement string. As we look at the regular expression "/^217.215.84.222.*\n/m", from left to right: ^ Start of line if modifier /m is used (completely right) <ip address>, followed by a dot (.). This dot means any characters, followed by a asterisk (*). The asterisk is a "0 or more quantifier", which matched everything until the next statement (in this case the "\n"). You can also use "$" instead of "\n", only the newline will not be stripped. "$" means end of line, while "\n" means newline. HTH, Erwin