MySQL and Array's REALLY simple question but I'm not GETTING it .. Ugh..

Can anyone tell me what's wrong with my code? All I get output from this is the LAST row of data from my Database. There are 2 rows, how do I make it pull data from all of the rows? It's not going through the loop like it should.... I need to be able to tell the mysql_fetch_array which row I want in each it iteration of the for loop. The For loop increments counter, but there is no syntax to add $counter to the result_type. The same goes with fetch_row... What am I forgetting!!?? I know it's something simple ******* $sql2 = mysql_connect("localhost", "eweb", "dbfun") or die("Could not connect <BR>"); mysql_select_db("actionregs", $sql2); $top_level = mysql_query("SELECT * FROM williams", $sql2) or die("Could not do query <BR>"); $sql2_results = mysql_fetch_array($top_level); $query_sql2_rows = mysql_num_rows($top_level); echo $query_sql2_rows; // echo's 2 rows print "<table style=\"font-family:Verdana; font-size:10pt\" border=0 cellpadding=4 width=90%>"; print "<tr bgcolor=\"#c0c0c0\"><th width=50>Action ID</th><th width=100>Owner</th><th width=250>Technology</th><th>Summary</th></tr>"; for ($counter=0; $counter < $query_sql2_rows; $counter++) { $tabledata = mysql_fetch_array($top_level); echo "<td>$tabledata[0]</td>"; echo "<td>$tabledata[6]</td>"; echo "<td>$tabledata[2]</td>"; echo "<td>$tabledata[3]</td>"; echo "</tr>"; } print "</table>"; Thanks.