Re: pass var through URL String

From: Date: Thu, 19 Sep 2002 23:13:03 +0000
Subject: Re: pass var through URL String
References: 1 2 3 4 5  Groups: php.general 
Request: Send a blank email to php-general+get-116944@lists.php.net to get a copy of this message
I was wrong, it is passing $bname. I have got it down to a syntax error by using. $sql = "SELECT * FROM bugs WHERE bname = {$_GET['bname']}"; gary Gary wrote:
I don't think it is being passed. I think I am going to have to figure out how to pass bname in the link using pear.With pear bnname=0 while ($row = $res->fetchRow()){
        $bname  = $row[0];
        $owner = $row[1];
           echo "
           <li><a href=\"temp_page.php?bname=$bname\">$bname</a> by $owner<li>
           ";
} Gary Kevin Stone wrote:
There's obviously something wrong with the way you're handeling the new variable. Do extract($_GET); and go back to the way you were handeling it before. echo $bname; -Kevin


« previous php.general (#116944) next »