AW: [PHP] print the name of a variable

Hi Bas, what do you mean with "NAME_OF_VARIABLE" You write the values of the variables "name, contact, function, adress" in an array. So you have fields[0] = value-of name fields[1] = value-of contact fields[2] = value-of function fields[3] = value-of adress You could do something like fields["name"] = $name fields["contact"] = $contact .. And read out by.. while (list($name, $value) = each($fields)) print "$name ==> $value <BR>"; You want to have the name of a variable, right ? Ok, how do you want to tell your script which variable you mean ; ) Hope that helps. Bye Jens -----Ursprungliche Nachricht----- Von: Bas Jochems [mailto:bas@webdisplay.nl] Gesendet: Dienstag, 15. August 2000 11:32 An: php-general@lists.php.net Betreff: [PHP] print the name of a variable Hello all, How can i print the name of a variable? I mean, when you have $name i want to add "name" to $body. Here's an example. $new_line = "\n<br>"; $fields = array($name, $contact, $function, $adress); $n = count($fields); for ($i = 0; $i < $n; $i++) { if ($fields[$i]) { // this is were i want to add the name of the variable to $body $body = $body."NAME_OF_VARIABLE"; $body = $body.$fields[$i]; $body = $body.$new_line; } } anyone knows how to solve this problem? thanks Bas -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net