Re: Re[2]: [PHP] counting words in a string

From: Date: Sat, 28 Sep 2002 17:26:31 +0000
Subject: Re: Re[2]: [PHP] counting words in a string
References: 1  Groups: php.general 
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You need to look at a few options... one is regular expression (not my forte), or perhaps winding through the string one character at a time, writing a very simple state engine. Justin French on 28/09/02 4:47 PM, rdkurth@starband.net (rdkurth@starband.net) wrote: > Hello Justin, > > That worked perfect but I have one more problem I need to know if one > of the word is UNAVAILABLE I need to know if it is the first one or > the second one. I don't know if there is any way to do this. > 1st 2nd > $string ="UNAVAILABLE AVAILABLE More Info"; > 1st 2nd > $string ="AVAILABLE More Info UNAVAILABLE "; > > Friday, September 27, 2002, 11:22:42 PM, you wrote: > > > JF> if this is your SPECIFIC problem, putting a space at the beginning of > $srch > JF> will help, eliminating XAVAILABLE... but this will cause a problem with > the > JF> word AVAILABLE appearing at the start of the string, so temporarily put a > JF> space at the start of the string: > > JF> <? > JF> // UNTESTED > JF> $count = substr_count(' '.strtolower($string), strtolower(' > JF> '.$srch)); > JF> echo $count; > ?>> > > JF> this won't help if there are newlines and other white space instead of > JF> spaces, and won't help (so far) for a different set of circumstances... > > JF> it would be nice to extend substr_count() could be extended to have an > JF> option. > > JF> Justin > > > > JF> on 28/09/02 3:41 PM, rdkurth@starband.net (rdkurth@starband.net) wrote: > >>> >>> I need to count how many times the word AVAILABLE appears in a string >>> like this >>> $string ="AVAILABLE More Info AVAILABLE More Info"; >>> some time the string looks like this >>> $string ="UNAVAILABLE More Info AVAILABLE More Info"; >>> or >>> $string ="AVAILABLE More Info UNAVAILABLE More Info"; >>> when I use >>> $srch="AVAILABLE"; >>> $count=substr_count(strtolower($string), strtolower($srch)); >>> echo $count; >>> it puts the count a 2 even when one of the words is UNAVAILABLE >>> how can I make it only count AVAILABLE and not UNAVAILABLE or visa >>> verse > > > >

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