Re: odd addition error<>?

From: Date: Tue, 15 Aug 2000 19:15:25 +0000
Subject: Re: odd addition error<>?
References: 1  Groups: php.general 
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On Tue, 15 Aug 2000, callen wrote: > Then after these two conditionals: > > $handling =2.00; > echo "Fee again is $fee <br>"; > $sh += $fee; > echo "SH is: $sh <br>"; > $sh += $handling; > echo "Sh is $sh"; //which prints "2" when coming from block2 > This is unlikely to help, but who knows. Maybe casting the $fee variable would help you. Try: $sh += (integer) $fee; Hope that helps, Joao -- Joao Prado Maia Web Developer Kefta.com, Inc

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