RE: [PHP] Help with multidimensional array setting up a mysql query..

From: Date: Wed, 16 Aug 2000 02:52:30 +0000
Subject: RE: [PHP] Help with multidimensional array setting up a mysql query..
References: 1  Groups: php.general 
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Chad you can use something like this: $subquery = substr($subquery, 0, -1); which just chops off the last character from the string. rgds - Jason Wong Digital View Ltd 2201 Nanyang Plaza 57 Hung To Road Kwun Tong HONG KONG Tel: +852-2861-3615 Fax: +852-2520-2987 www.digitalview.com > -----Original Message----- > From: Chad Day [mailto:cday@beachassociates.com] > Sent: 15 August 2000 22:47 > To: 'php-general@lists.php.net' > Subject: [PHP] Help with multidimensional array setting up a mysql > query.. > The problem is that the statements are printing out like: > > SELECT ABEPN, CABEPN, DESCRIPTION, QUANTITY, PRICE, from abeparts where > ABEPN like PARTNUM > SELECT GUDENPN, CGUDENPN, DESCRIPTION, PRICE, from gudenparts > where GUDENPN > like PARTNUM > > which is REALLY CLOSE to what I want. The problem is the last array > element, (PRICE).. it adds the comma after it, which I > understand why it > does. I just don't know how to write something to say "Hey, > this is the > last element in the array, so $subquery .= " $val", not $subquery .= " > $val,". > > I tried to get a count or sizeof the array, and I could loop > based on that > easily, but for some reason I can't seem to obtain the count/sizeof my > multidimensonal arrays correctly. Can anyone help? > > Thanks, > Chad > > > Chad Day > Beach Associates > > When I speak german... I think german in my head... but > like...Do skript > kiddies see a w40l3 8uncha 1's and 0's and 3's and 4's and 7's in > their > h34d'5 w43n t43y R +a1k1n6 ? -- SirStanley > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: > php-list-admin@lists.php.net >

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