Re: NewB PHP / mysql Q

From: Date: Thu, 10 Oct 2002 15:36:17 +0000
Subject: Re: NewB PHP / mysql Q
References: 1  Groups: php.general 
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The problem is that array keys are case sensitive. You can use what you've got, but the case has to match what you're selecting in your query. I see you are trying to use $row['UName'] but I don't see you selecting that in your query. ---John Holmes... ----- Original Message ----- From: "Timothy J Hitchens" <tim@hitcho.com.au> To: <php-general@lists.php.net> Sent: Thursday, October 10, 2002 9:33 AM Subject: RE: [PHP] NewB PHP / mysql Q > Try this.. > > select u.id, u.lname as lastname, u.frname as firstname, ... etc > > oh and the reason you get an error is that you can't have a dot in a > variable etc... > > > > Timothy Hitchens (HITCHO) > tim@hitcho.com.au > > HITCHO has Spoken! > > > > > > > -----Original Message----- > From: inpho [mailto:inphorm@gmx.net] > Sent: Thursday, 10 October 2002 4:19 PM > To: php-general@lists.php.net > Subject: [PHP] NewB PHP / mysql Q > > > Hi all, > > I need a bit of quick help here.... > I've joined 2 tables together with this code here: > > $result=mysql_query("select u.id, u.cid, u.lname, u.fname, u.vld, c.id, > c.cname from tblclient u, tblcompany c where u.vld=1 and u.cid = > c.id",$db); > > then I put it into an array: > > while ($row=mysql_fetch_array($result)) { > print "<tr><td>$row[UName]</td><td>$row[FName] > $row[LName]</td>$row[cname]<td></td></tr>"; > } > > but the $row[xxx] aren't displaying any info, if I put $row[u.unam] it > returns an error. I run the SQL query in phpmyadmin and it runs fine, > returning 2 results how do I access those results through an array??? > > - inpho - > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >

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