RE: [PHP] =.jpg from another URL with PHP=

Save your first bit of code in a file (e.g.: image.php) Your HTML file should look like this: <html> <head>...</head> <body> ..... <img src="image.php" .....> .... </body> </html> Regards, Daniel Kushner _________________________________________ Need hosting? http://thehostingcompany.us -----Original Message----- From: Anthony Ritter [mailto:tony@gonefishingguideservice.com] Sent: Friday, October 11, 2002 11:53 AM To: php-general@lists.php.net Subject: [PHP] =.jpg from another URL with PHP= The following script picks up single .jpg image of a doppler weather map from another URL: ....................................... <? $theURL="http://image.weather.com/web/radar/us_har_closeradar_medium_usen.jp g"; if(!($fp=fopen($theURL, "r"))) { print("Could not open the URL."); exit; } $contents=fread($fp,1000000); print($contents); fclose($fp); ?> ...................................... However, when I try to insert the HTML tages into the script like: ...................................................... <HTML> <HEAD> <BODY> This is a map. <? $theURL="http://image.weather.com/web/radar/us_har_closeradar_medium_usen.jp g"; if(!($fp=fopen($theURL, "r"))) { print("Could not open the URL."); exit; } $contents=fread($fp,1000000); print($contents); fclose($fp); ?> </BODY> </HTML> .......................................................... I get the following: ״אJFIF




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