Re: passing mysql_error() out put to a different page?

And also on the folloving page use echo htmlspecialchars(stripslashes($_GET['err_value'])); John W. Holmes wrote:

Well, the die() function takes a limited number of parameters, which

as

you noted is why it doesn't like the assignment of the mysql_error() and

the

header statements both inside the die() function. So, why not something like this: $res = mysql_query(.....); if ($res == FALSE) //which is what I _believe_ die() looks at /* or at least this is what the manual says the function returns on a query error */ { $error = mysql_error(); Header("Location: logerror.php?op=insert_error&err_value=$error");

If you do it this way, you'll want to urlencode(), rawurlencode(), or base64_encode() the $error. You only have to decode on the receiving end if you use the base64_encode. ---John Holmes...