Help please.
| From: | Steve Jackson | Date: | Fri, 01 Nov 2002 14:04:21 +0000 |
| Subject: | Help please. | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-122419@lists.php.net to get a copy of this message | ||
Hi,
I have been trying for most of the day to pull a variable from a db.
Finally managed that. Now I need to pass the result of a function to
another function.
How do you do this?
I assume the following if called in another page can be used?
function get_shipping($shipping)
{
$conn = db_connect();
$query = "SELECT * FROM receipts ORDER BY receipt_id DESC LIMIT 1";
$result = mysql_query($query);
//$shippingvar = $myrow["shipping"];
if(mysql_numrows($result)>0)
$shipping = mysql_result($result, 0, "shipping");
return $shipping;
}
If I return $shipping how can I display that?
I have called it in another page by doing
get_shipping($shipping)
And then
Echo "test $shipping";
But that doesn't work.
Ideas where I'm going wrong this time?
Steve Jackson
Web Developer
Viola Systems Ltd.
http://www.violasystems.com
stephen.jackson@violasystems.com
Mobile +358 50 343 5159