Re: $_FILES

How about just print_r($_FILES); Does that return anything? ---John Holmes... ----- Original Message ----- From: "Salvador Ramirez" <sram@profc.udec.CL> To: "PHP General" <php-general@lists.php.net> Sent: Monday, November 04, 2002 3:50 PM Subject: [PHP] $_FILES > Hi, > > I hope somebody could help me with a problem I have with the $_FILES > variable. > > I'm trying to make a PHP script which could have access to an uploaded > remote file. The piece of HTML is: > > ---------------- > <html> > <body> > > <form action="ll.php" method="post" > enctype="multipart/form-data"> > <input name="userfile" size=48 type="file"> > <input type="submit" name="attach" value="Add"><br> > </form> > > </body> > </html> > ---------------- > > and the ll.php script is: > > ---------------- > <?php > printf("file=(%s)<br>", $_FILES['userfile']['name']); > print_r(array_values($_FILES)); > phpinfo(); > ?> > ---------------- > > but the variable $_FILES is not set at all, because the printf doesn't > print the name of the uploaded file nor the second line, the print_r() > print anything for that array variable. > So the question is: what could be happening that the variable $_FILES is > not set? > > The phpinfo() function returns PHP 4.2.3, and I compiled it with the > following configure line: > > './configure' '--with-mysql' > '--with-apxs=/server/www/apache-1.3.26/bin/apxs' '--with-imap' > '--with-imap-ssl' '--enable-track-vars' '--enable-dbase' > '--with-pgsql=/server/postgresql' > > over an apache 1.3.26. > > Any help will be very appreciated. > > Thanks in advance. > > ---sram > "Don't listen to what I say; listen to what I mean!" --Feynman > Salvador Ramirez Flandes PROFC, Universidad de Concepcion, CHILE > http://www.profc.udec.cl/~sram > mailto:sram@profc.udec.cl > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >