RE: [PHP] Graphics question

The reason "imagedestroy()" may have not worked for you is that maybe imagedestroy() is misspelled? If you misspelled it in the code then it won't work. Just a suggestion. - Darwin > -----Original Message----- > From: Robbert van Andel [mailto:robbert@vafam.com] > Sent: Thursday, November 07, 2002 9:30 PM > To: php-general@lists.php.net > Subject: [PHP] Graphics question > > > I have created a webpage that builds a table and graph using the GD > functions. When I switch to another page or select a different month to > build the table for, the graph.jpg does not rebuild. I have to press > reload to make the graph render using the new data. I have used > imagedistroy($pic) in the hopes that this will work, but it didn't. > > To elaborate on the situation, I first call imagecreate, then run the > code to create the bar graph. I then use > > imagejpg($pic,$graphname) (or something ot that affect. I don't have > access to the code at home). > > I then show the picture using > > echo "<img src=\"$graph\">"; > > Finally I call imagedestroy($pic). Do you have any suggestions? > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >