Re: Other Notice problem...

Try if (isset ($status) && $status == 'ADD') instead... this should take care of the error--IF you're sure that the fact that the $status variable is not set at that point is ok. Marco ------------- php|architect -- The Monthly Magazine For PHP Professionals Come visit us on the web at http://www.phparch.com! On Fri, 2002-11-08 at 11:04, R B wrote: > My code is: > > <?php > some code..... > .... > .... > > if ($status == "ADD") { > > some code ... > ... > ... > } > ?> > The message is: "Notice: Undefined variable: status in ...." > > I'm going to explain how my script work. > I have an php page (addProduct.php) with an input form. I have 2 buttons > (add and cancel) and a hidden control with name=status. If i press the add > button, the page submit the form data to the same page (<form > action="addProduct.php">) with status hidden control name set to ADD, so the > if statement its true only if i press the add button. > I see the message when i call the page to add the data not when i submit the > data. > > How can i fix the problem? or there is another best way to do this? > > > > >From: Marco Tabini <marcot@tabini.ca> > >To: R B <rbphp@hotmail.com> > >CC: php-general@lists.php.net > >Subject: Re: [PHP] Other Notice problem... > >Date: 08 Nov 2002 10:25:46 -0500 > > > >This usually means that you're using a variable without having > >initialized it. For example > > > >$a = $b + 1; > > > >will give you that warning if no value is assigned to $b prior to this > >line. It's PHP's way of telling you that you might be doing something > >wrong. > > > >Perhaps if you post some of your code we can help better? > > > > > >Marco > > > >------------- > >php|architect -- The Monthly Magazine For PHP Professionals > >Come visit us on the web at http://www.phparch.com! > > > >On Fri, 2002-11-08 at 10:31, R B wrote: > > > This is not the same question i asked yesterday. > > > > > > When i set error_reporting = E_ALL and display_errors = On in my > >php.ini, > > > i get the next message: > > > > > > "Notice: Undefined variable: varname in ....". > > > > > > How can i fix this problem without setting error_reporting = E_ALL & > > > ~E_NOTICE and/or display_errors = Off, or what way do you think is the > >best > > > to resolve this problem? > > > > > > Thanks, > > > > > > RB > > > > > > > > > > > > _________________________________________________________________ > > > Charla con tus amigos en línea mediante MSN Messenger: > > > http://messenger.microsoft.com/es > > > > > > > > > -- > > > PHP General Mailing List (http://www.php.net/) > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > _________________________________________________________________ > MSN. Más Útil Cada Día http://www.msn.es/intmap/ >