Re: preg_match_all - how does it work?

Hi Randall, If you look closely at the definition of preg_match_all(), you'll see that it generates an array of arrays--that's because, for each match, it generates an array that corresponds to the result of a single call to preg_match, then puts all the resulting array into another array. If you use PREG_SET_ORDER, your $match array contains an array for each of the matches found. Each array then contains: * The entire matched string in element 0 * Each of the substring (defined in brackets in your pattern) starting from array 1. Hope this helps! Marco -- ------------ php|architect - The magazine for PHP Professionals The first monthly worldwide magazine dedicated to PHP programmers Check us out on the web at http://www.phparch.com On Sun, 2002-11-17 at 11:13, Randall Perry wrote: > I have some experience in using regular expressions in Perl, and have been > able to use preg_match in php, but am having a problem with preg_match_all. > > I'm trying to extract data from an HTML table. Here's my preg_match call > that correctly grabs the 1st row of data in the table. It grabs 4 columns of > data: > > preg_match("|<tr > > class=\"CART_TD_REG\".+?<td.+?>(.*?)<.+?<td.+?>(.*?)<.+?<td.+?>(.*?)<.*?<inp > ut.*?>[&nbsp;]*(.*?)</td>.*?</tr>|", $res, $match); > > If I use preg_match_all on the same table: > preg_match_all("|<tr > > class=\"CART_TD_REG\".+?<td.+?>(.*?)<.+?<td.+?>(.*?)<.+?<td.+?>(.*?)<.*?<inp > ut.*?>[&nbsp;]*(.*?)</td>.*?</tr>|", $res, $match, PREG_PATTERN_ORDER); > > ...and try to print output, I get: > > $match[0] = Array > $match[0][0] = Array[0] > $match[1][0] = Array[0] > $match[0][1] = Array[0] > $match[1][1] = Array[0] > > > Same result with PREG_SETORDER. > > What am I doing wrong? > > -- > Randall Perry > sysTame > > Xserve Web Hosting/Co-location > Website Development/Promotion > Mac Consulting/Sales > > http://www.systame.com/ > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >