Re: How to: If($var != '#' OR '#')

Quoting Jason Wong <php-general@gremlins.biz>: > On Thursday 21 November 2002 01:34, Ryan Gallagher wrote: > > > Try: > > > > if( ( $_GET['sc'] != 2 ) OR ( $_GET['sc'] != 8 ) ){ > > /* > > * Do Foo provided sc is anything but a 2 or 8 > > */ > > do foo; > > } > > > > Assuming of course that you meant to exclude cases of 2 or 8. It's a bit > > hard to tell what your intended event for 8 is. > > The above would not have the intended effect. My boolean maths is extremely > rusty but I think it is equivalent to saying: > > if (!($_GET['sc'] == 2 AND $_GET['sc'] == 8)) > > Which means your code above is *always* TRUE, so do foo is always executed! > > In any case you can easily test it by mentally plugging in values 1 to 8 for > > $_GET['sc'] and evaluating it for yourself. I'll shut up now, teaches me to reply to this list too early in the morning and without coffee. ;-) BTW, what I posted would ALWAYS execute, because of _OR_. If it's 2, then it's not 8, so one of the two sides would be true. Here's a corrected one: if( ( $_GET['sc'] != 2 ) AND ( $_GET['sc'] != 8 ) ){ /* * Do Foo provided sc is anything but a 2 or 8 */ do foo; } -- Ryan T. Gallagher ryan@studiesabroad.com International Studies Abroad http://www.studiesabroad.com (512)480-8522