RE: [PHP] preg_replace wierdness
| From: | John W. Holmes | Date: | Sat, 23 Nov 2002 00:55:27 +0000 |
| Subject: | RE: [PHP] preg_replace wierdness | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-125696@lists.php.net to get a copy of this message | ||
> Code snippet ->
> <?php
>
> header('Content-type: text/plain');
>
> $foo = '<img src="images/php.png"> <img
> src="images/apache.png">';
>
> echo "$foo\n";
>
>
> $path = '../../../';
> $bar = preg_replace('/(<img src=")(.*">)/', "$1" . $path .
> "$2",
$foo);
>
> echo $bar;
It's being greedy. Your pattern is matching
(<img src=") & (images/php.png"> <img src="images/apache.png">)
and inserting $path between the two.
Use
$bar = preg_replace('/(<img src=")(.*">)/U',"$1" . $path .
"$2", $foo);
Quote:
U (PCRE_UNGREEDY)
This modifier inverts the "greediness" of the quantifiers so that they
are not greedy by default, but become greedy if followed by "?". It is
not compatible with Perl. It can also be set by a (?U) modifier setting
within the pattern.
---John Holmes...