Re: function args declared by-reference, with default value?

Nick Eby wrote:

true or false: when declaring a function, a given argument can be declared to pass by reference, or can be declared to have a default value, but never both. i.e., you can only write one of: function foo(&$param) function foo($param = "bar") but never the equivalent of: function foo(&$param = "bar") is there a way to declare an argument with both pass-by-reference and default-value properties?

No, but this will be supported by Zend Engine 2, which will drive PHP 5 and higher. -- ------------------------------------------------------------------------- Derick Rethans http://derickrethans.nl/ PHP Magazine - PHP Magazine for Professionals http://php-mag.net/ -------------------------------------------------------------------------