Re: Function passed as argument to function

On Saturday 30 November 2002 03:14 pm, you wrote: > On Sunday 01 December 2002 03:54, Jeffrey B.Ferland wrote: > > std_layout("Title here", list_writings(poetry)) > > > > both std_layout and list_writings are user-defined functions. > > std_layout() echo's the two arguments that it takes at select points in > > its execution. I want to the output of list_writings() to be an argument > > for std_layout(). > > Hmm, what's the problem then? > > Functions take any valid expressions as arguments. If list_writings() > returns a valid expression then you should have no problems at all. For reference, see http://autocracy.homelinux.org/template.php and http://autocracy.homelinux.org/error.php template.php is the proper layout, and uses the same code as error.php, with the exception that "LEFT SIDE TEXT" has been replaced with 'list_writings(poetry)'. Note that the output from that function occurs where it was placed within the code, not where it was called to... Basically, instead of the output from list_writings(poetry) being passed to the function, it simply executes. -Jeff SIG: HUP