Re: Test links?

Not sure how to supress the warning message that PHP automatically does when you haven't got a valid URL though. should be able to surpress errors by adding an * before the result variable *$fp = fopen($linkdata['linkurl'],"r"); Hope this helps--or even works for this particular problem. Hugh ----- Original Message ----- From: "Beth Gore" <bethgore@tesco.net> To: <php-general@lists.php.net> Sent: Saturday, November 30, 2002 11:02 AM Subject: Re: [PHP] Test links? > Rob Packer wrote: > > >Okay, I'm confused... file, fopen, and fsockopen seem to say not found on > >alot valid URLs... does this look to be correct usage? > >$url = $row[0]; // just get the url from the db > >$fp = implode ('', file ($url)); > > if (!$fp) {echo "<font color=red><b>Unable to access > > file</b></font>"; } > > else { fclose($fp); echo "The link is working!"; } > > > >It seems I always get this warning... > > > >Warning: Supplied argument is not a valid File-Handle resource in > >/web/home/nrc.net/www/robert/links4.php on line 11 > > > >If someone can tell me what I'm doing wrong, I'd appreciate it. > > > >Thanks, > > Robert > > > > > > > > > > > When fopen successfully opens a file it populates an array > $http_response_header, which you can examine to see if the link works or > not - I don't believe you can actually get the file itself, but since > that's not what we're after that's not a problem! > > Having said that, fopen produces a very annoying error if it doesn't > find the page, but I found the following works: > > <?php > > $SQL = "SELECT linkurl, linkID FROM links"; > $result = mysql_query($SQL); > > while($linkdata = mysql_fetch_array($result)){ > > $fp = fopen($linkdata['linkurl'],"r"); > if($fp) > { > echo "<p>".$linkdata['linkurl']." is still > valid.</p>"; > > }else{ > > echo "<p>".$linkdata['linkurl']." is invalid. Updating > database... "; > > $SQL = "UPDATE links SET status = 0 WHERE linkID = > '".$linkdata['linkID']."'"; > $result2 = mysql_query($SQL); > if($result2) > { > echo "Database updated</p>"; > } > } > > } > ?> > > Rather than deleting the link, it's probably better to set a flag to > show it was invalid last time you checked, but check it again next time. > Or you could keep a count of the number of failed attempts, and delete > if it goes beyond 3 or so. > > Not sure how to supress the warning message that PHP automatically does > when you haven't got a valid URL though. > > Hope this works for you! > > Beth Gore > -- > http://bethanoia.dyndns.org > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >