Re: How to loop diplays of 4 column of items, every row?

asuming $res holds your query result: $col=0; echo '<table>'; while($img=mysql_fetch_array($res)) { if($col==0) echo '<tr>'; echo "<td> <img src="$img[thumb]"> </td>"; $col++; if($col==4) {

       echo '</tr>';
       $col=0;

} } if($col!=0) str_repeat('<td></td>', 4 - $col); echo '</table>'; Not tested Wee Keat [Amorphosium] wrote:

Hi all... I've tried to figure this one out but I'm really having a headache now. So, I really need your help. Situation: I have a database of images and its own thumbnails created using GD. It worked wonderfully. Problem: I want to display ONLY thumbnails in table form, incrementing in rows of 4 columns. By this I mean that I want to write a script which loops in a way that it displays 4 pictures withdrawn from the database into a row, and then for the next 4 images, displays them into the next row. If you don't understand see the gif below... a script that displays 4 pictures across first ( arrow 1) , then goes to the next row and displays the next 4 ( arrow 2). I can't work out how can i structure my loop to do this. Question: Can all the gurus out there please give me a pointer? I really can't work out the logic or systematic flow of scripting this one. Thank you so much in advance! Yours, Wee Keat Chin ------------------------------------------ "Two things are infinite: the universe and human stupidity; and I'm not sure about the the universe." - Albert Einstein