Using fopen() to open a php file with variables.
| From: | Jay \(PHP List\) | Date: | Thu, 12 Dec 2002 01:40:21 +0000 |
| Subject: | Using fopen() to open a php file with variables. | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-127943@lists.php.net to get a copy of this message | ||
Okay, I need to retrieve the output of a php file with variables being
passed to it. Example:
$calendar_file = "make_calendar.php3?month=$month&year=$year";
$fp = $fp = fopen("$calendar_file", "r");
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
$calendar_html .= $buffer;
}
fclose($fp);
It gives me an error that the file doesn't exist, but it does. Any
suggestions?
Jay Douglas
Systems Consultant
Fort Collins, CO